An object is dropped from rest. Its v-t graph is

Question

An object is dropped from rest. Its v-t graph is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

From first equation of motion v=u+at as object starts from rest, so u=0 ∴ v=at or v propto t Therefore, v-t graph is a straight line passing through 0.

Q. An object is dropped from rest. Its $v - t$ graph is

From first equation of motion $v = u + a t$ as object starts from rest, so $u = 0$ $∴$ $v = a t$ or $v \propto t$ Therefore, $v - t$ graph is a straight line passing through 0.

Q. An object is dropped from rest. Its v−t graph is

From first equation of motion v=u+at as object starts from rest, so u=0 ∴ v=at or v∝t Therefore, v−t graph is a straight line passing through 0.

Q. An object is dropped from rest. Its $v - t$ graph is

From first equation of motion $v = u + a t$ as object starts from rest, so $u = 0$ $∴$ $v = a t$ or $v \propto t$ Therefore, $v - t$ graph is a straight line passing through 0.