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  4. An object is dropped from rest. Its v-t graph is

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Q. An object is dropped from rest. Its $ v-t $ graph is

KEAMKEAM 2008

Solution:

From first equation of motion $ v=u+at $ as object starts from rest, so $ u=0 $ $ \therefore $ $ v=at $ or $ v\propto t $ Therefore, $ v-t $ graph is a straight line passing through 0.