An LCR series circuit is connected to a source of alternating current. At resonance the applied voltage and current flowing through the circuit will have a phase difference of :

Question

An LCR series circuit is connected to a source of alternating current. At resonance the applied voltage and current flowing through the circuit will have a phase difference of : (A) zero (B)  (π /4)  (C)  (π /2)  (D)  π

Tardigrade Admin · Accepted Answer

In a series LCR circuit the phase angle is given by tan φ =(ω L-(1/ω C)/R) At resonance ω L-(1/ω C), then tan φ =0, i.e., φ =0

Q. An LCR series circuit is connected to a source of alternating current. At resonance the applied voltage and current flowing through the circuit will have a phase difference of :

zero

$\frac{π}{4}$

$\frac{π}{2}$

$π$

In a series LCR circuit the phase angle is given by
$tan ϕ = \frac{ω L - \frac{1}{ω C}}{R}$
At resonance $ω L - \frac{1}{ω C},$
then $tan ϕ = 0,$ i.e., $ϕ = 0$

Q. An LCR series circuit is connected to a source of alternating current. At resonance the applied voltage and current flowing through the circuit will have a phase difference of :

zero

4π​

2π​

π

In a series LCR circuit the phase angle is given by tanϕ=RωL−ωC1​​ At resonance ωL−ωC1​, then tanϕ=0, i.e., ϕ=0

$\frac{π}{4}$

$\frac{π}{2}$

$π$

In a series LCR circuit the phase angle is given by
$tan ϕ = \frac{ω L - \frac{1}{ω C}}{R}$
At resonance $ω L - \frac{1}{ω C},$
then $tan ϕ = 0,$ i.e., $ϕ = 0$