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Q. An LCR series circuit is connected to a source of alternating current. At resonance the applied voltage and current flowing through the circuit will have a phase difference of :

J & K CETJ & K CET 2001

Solution:

In a series LCR circuit the phase angle is given by
$ \tan \phi =\frac{\omega L-\frac{1}{\omega C}}{R} $
At resonance $ \omega L-\frac{1}{\omega C}, $
then $ \tan \,\phi =0, $ i.e., $ \,\phi =0 $

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