An L-C circuit is in the state of resonance. If C=0.1 μ F and L=0.25 H, neglecting ohmic resistance of circuit, what is the frequency of oscillations?

Question

An L-C circuit is in the state of resonance. If C=0.1 μ F and L=0.25 H, neglecting ohmic resistance of circuit, what is the frequency of oscillations? (A) 1007 Hz (B) 100 Hz (C) 109 Hz (D) 500 Hz

Tardigrade Admin · Accepted Answer

From the formula, the frequency of oscillation is f =(1/2 π √L C) =(1/2 π √0.25 × 0.1 × 10-6) ≈ 1007 Hz

Q. An $L - C$ circuit is in the state of resonance. If $C = 0.1 μ F$ and $L = 0.25 H$ , neglecting ohmic resistance of circuit, what is the frequency of oscillations?

1007 Hz

100 Hz

109 Hz

500 Hz

From the formula, the frequency of oscillation is
$f = \frac{1}{2 π L C}$
$= \frac{1}{2 π 0.25 \times 0.1 \times 1 0 ^{- 6}}$
$\approx 1007 Hz$

Q. An L−C circuit is in the state of resonance. If C=0.1μF and L=0.25H, neglecting ohmic resistance of circuit, what is the frequency of oscillations?