Question

An $L-C$ circuit is in the state of resonance. If $C=0.1\, \mu F$ and $L=0.25\, H$, neglecting ohmic resistance of circuit, what is the frequency of oscillations?

• A. 1007 Hz
• B. 100 Hz
• C. 109 Hz
• D. 500 Hz

Answer 1

Answer: (A)

From the formula, the frequency of oscillation is
$f =\frac{1}{2 \pi \sqrt{L C}}$
$=\frac{1}{2 \pi \sqrt{0.25 \times 0.1 \times 10^{-6}}}$
$\approx 1007\, Hz$