An iron rod is placed parallel to magnetic field of intensity 2000 A m . The magnetic flux through the rod is 6× 10- 4 Wb and its cross-sectional area is 3 cm2 . The magnetic permeability of the rod in Wb A- 1m- 1 is

Question

An iron rod is placed parallel to magnetic field of intensity 2000 A m . The magnetic flux through the rod is 6× 10- 4 Wb and its cross-sectional area is 3 cm2 . The magnetic permeability of the rod in Wb A- 1m- 1 is (A) 10- 1 (B) 10- 2 (C) 10- 3  (D) 10- 4

Tardigrade Admin · Accepted Answer

μ =(φ/A)× (1/H)=(6 × 10- 4/3 × 10- 4)× (1/2 × 103)=10- 3WbA- 1m- 1

Q. An iron rod is placed parallel to magnetic field of intensity $2000 A m$ . The magnetic flux through the rod is $6 \times 1 0^{- 4} Wb$ and its cross-sectional area is $3 c m^{2}$ . The magnetic permeability of the rod in $Wb A^{- 1} m^{- 1}$ is

$1 0^{- 1}$

$1 0^{- 2}$

$1 0^{- 3}$

$1 0^{- 4}$

$μ = \frac{ϕ}{A} \times \frac{1}{H} = \frac{6 \times 1 0 ^{- 4}}{3 \times 1 0 ^{- 4}} \times \frac{1}{2 \times 1 0 ^{3}} = 1 0^{- 3} Wb A^{- 1} m^{- 1}$

Q. An iron rod is placed parallel to magnetic field of intensity 2000Am . The magnetic flux through the rod is 6×10−4Wb and its cross-sectional area is 3cm2 . The magnetic permeability of the rod in WbA−1m−1 is

10−1

10−2

10−3

10−4