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  4. An iron rod is placed parallel to magnetic field of intensity 2000 A m . The magnetic flux through the rod is 6× 10- 4 Wb and its cross-sectional area is 3 cm2 . The magnetic permeability of the rod in Wb A- 1m- 1 is

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Q. An iron rod is placed parallel to magnetic field of intensity $2000 \, A \, m$ . The magnetic flux through the rod is $6\times 10^{- 4} \, Wb$ and its cross-sectional area is $3 \, cm^{2}$ . The magnetic permeability of the rod in $Wb \, A^{- 1}m^{- 1}$ is

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Solution:

$\mu =\frac{\phi}{A}\times \frac{1}{H}=\frac{6 \times 10^{- 4}}{3 \times 10^{- 4}}\times \frac{1}{2 \times 10^{3}}=10^{- 3}WbA^{- 1}m^{- 1}$