An inductor of inductance L and resistor R are joined together in series and connected by a source of frequency ω. The power dissipated in the circuit is

Question

An inductor of inductance L and resistor R are joined together in series and connected by a source of frequency ω. The power dissipated in the circuit is (A) (V/R2+ω2L2) (B) (R2+ω2L2/V) (C) (V2R/√R2+ω2L2) (D) (V2R/R2+ω2L2)

Tardigrade Admin · Accepted Answer

I=(v/√R2+ω2L2) P=l2R=(v2R/R2+ω2 L2)

Q. An inductor of inductance L and resistor R are joined together in series and connected by a source of frequency $ω$ . The power dissipated in the circuit is

$\frac{V}{R ^{2} + ω ^{2} L ^{2}}$

$\frac{R ^{2} + ω ^{2} L ^{2}}{V}$

$\frac{V ^{2} R}{R ^{2} + ω ^{2} L ^{2}}$

$\frac{V ^{2} R}{R ^{2} + ω ^{2} L ^{2}}$

$I = \frac{v}{R ^{2} + ω ^{2} L ^{2}}$
$P = l^{2} R = \frac{v ^{2} R}{R ^{2} + ω ^{2} L ^{2}}$

Q. An inductor of inductance L and resistor R are joined together in series and connected by a source of frequency ω. The power dissipated in the circuit is

R2+ω2L2V​

VR2+ω2L2​

R2+ω2L2​V2R​

R2+ω2L2V2R​

I=R2+ω2L2​v​ P=l2R=R2+ω2L2v2R​

Q. An inductor of inductance L and resistor R are joined together in series and connected by a source of frequency $ω$ . The power dissipated in the circuit is

$\frac{V}{R ^{2} + ω ^{2} L ^{2}}$

$\frac{R ^{2} + ω ^{2} L ^{2}}{V}$

$\frac{V ^{2} R}{R ^{2} + ω ^{2} L ^{2}}$

$\frac{V ^{2} R}{R ^{2} + ω ^{2} L ^{2}}$

$I = \frac{v}{R ^{2} + ω ^{2} L ^{2}}$
$P = l^{2} R = \frac{v ^{2} R}{R ^{2} + ω ^{2} L ^{2}}$