Question

An inductor of inductance L and resistor R are joined together in series and connected by a source of frequency $\omega$. The power dissipated in the circuit is

• A. $\frac{V}{R^2+\omega^2L^2}$
• B. $\frac{R^2+\omega^2L^2}{V}$
• C. $\frac{V^2R}{\sqrt{R^2+\omega^2L^2}}$
• D. $\frac{V^2R}{R^2+\omega^2L^2}$

Answer 1

Answer: (D)

$I=\frac{v}{\sqrt{R^{2}+\omega^{2}L^{2}}}$
$P=l^{2}R=\frac{v^{2}R}{R^{2}+\omega^{2} L^{2}}$