An ideal monoatomic gas expands to twice its original volume such that its pressure P propto (1/V5/3) where V is the volume, the molar heat capacity of the gas is

Question

An ideal monoatomic gas expands to twice its original volume such that its pressure P propto (1/V5/3) where V is the volume, the molar heat capacity of the gas is (A) R (B) 3R (C) 2R (D) Zero

Tardigrade Admin · Accepted Answer

PV5/3 = constant C = Cv - (R/N-1) = (3/2)R - (R/(5)3-1)= Zero

Q. An ideal monoatomic gas expands to twice its original volume such that its pressure $P \propto \frac{1}{V ^{5/3}}$ where V is the volume, the molar heat capacity of the gas is

R

3R

2R

Zero

$P V^{5/3} = co n s t an t$
$C = C_{v} - \frac{R}{N - 1} = \frac{3}{2} R - \frac{R}{\frac{5}{3} - 1} = Z ero$

Q. An ideal monoatomic gas expands to twice its original volume such that its pressure P∝V5/31​ where V is the volume, the molar heat capacity of the gas is

R

3R

2R

Zero

PV5/3=constant C=Cv​−N−1R​=23​R−35​−1R​=Zero

Q. An ideal monoatomic gas expands to twice its original volume such that its pressure $P \propto \frac{1}{V ^{5/3}}$ where V is the volume, the molar heat capacity of the gas is

$P V^{5/3} = co n s t an t$
$C = C_{v} - \frac{R}{N - 1} = \frac{3}{2} R - \frac{R}{\frac{5}{3} - 1} = Z ero$