Question

An ideal gas occupies a volume of $2m^3$ at a pressure of $3\times 10^{6}Pa$. The energy of the gas is:

• A. $3\times 10^{6}J$
• B. $10^{8}J$
• C. $6\times 10^{4}J$
• D. $9\times 10^{-6}J$

Answer 1

Answer: (D)

Energy $=\frac{1}{2}nRT=\frac{f}{2}PV$
$=\frac{f}{2}\left(3\times 10^6\right)\left(2\right)$
$=f\times 3\times 10^6$
Considering gas is monoatomic i.e. $f=3$
$E.=9\times 10^{6}J$