Question

An ideal gas is allowed to expand from $1L$ to $10L$ against a constant external pressure of $1$ bar. Calculate the work done in $kJ$.

Answer 1

Answer: -0.9

$w=-P\Delta V$
$=-\left(1bar\right)\times \left(9L\right)$
$=-\left(10^{5}pa\right)\times \left(9\times 10^{-3}\right)m^3$
$=-9\times 10^{2}Nm$
$=-900J=-0.9kJ$