An ideal gas heat engine operates in a Carnot cycle between 227° C and 127° C. It absorbs 6 kcal at the higher temperature. The amount of heat (in kcal) converted into work is equal to

Question

An ideal gas heat engine operates in a Carnot cycle between 227° C and 127° C. It absorbs 6 kcal at the higher temperature. The amount of heat (in kcal) converted into work is equal to (A) 4.8 (B) 3.5 (C) 1.6 (D) 1.2

Tardigrade Admin · Accepted Answer

Efficiency of Carnot engine = (W/Q1)=1- (T2/T1) (W/6)=1- (400/500)= (1/5) ⇒ W= (6/5)=1.2 k cal.

Q. An ideal gas heat engine operates in a Carnot cycle between $22 7^{\circ} C$ and $12 7^{\circ} C .$ It absorbs $6 k c a l$ at the higher temperature. The amount of heat (in kcal) converted into work is equal to

4.8

3.5

1.6

1.2

Efficiency of Carnot engine
$= \frac{W}{Q _{1}} = 1 - \frac{T _{2}}{T _{1}}$
$\frac{W}{6} = 1 - \frac{400}{500} = \frac{1}{5}$
$\Rightarrow W = \frac{6}{5} = 1.2 k c a l .$

Q. An ideal gas heat engine operates in a Carnot cycle between 227∘C and 127∘C. It absorbs 6kcal at the higher temperature. The amount of heat (in kcal) converted into work is equal to

4.8

3.5

1.6

1.2

Efficiency of Carnot engine =Q1​W​=1−T1​T2​​ 6W​=1−500400​=51​ ⇒W=56​=1.2kcal.

Q. An ideal gas heat engine operates in a Carnot cycle between $22 7^{\circ} C$ and $12 7^{\circ} C .$ It absorbs $6 k c a l$ at the higher temperature. The amount of heat (in kcal) converted into work is equal to

Efficiency of Carnot engine
$= \frac{W}{Q _{1}} = 1 - \frac{T _{2}}{T _{1}}$
$\frac{W}{6} = 1 - \frac{400}{500} = \frac{1}{5}$
$\Rightarrow W = \frac{6}{5} = 1.2 k c a l .$