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Q. An ideal gas heat engine operates in a Carnot cycle between $227^{\circ} C $ and $127^{\circ} C. $ It absorbs $6\, kcal$ at the higher temperature. The amount of heat (in kcal) converted into work is equal to

AIPMTAIPMT 2003Thermodynamics

Solution:

Efficiency of Carnot engine
$= \frac {W}{Q_1}=1- \frac {T_2}{T_1}$
$\frac {W}{6}=1- \frac {400}{500}= \frac {1}{5}$
$\Rightarrow W=\frac {6}{5}=1.2 \, k cal.$