An ideal fluid flows through a pipe of circular cross-section made of two sections with diameters 2.5 cm and 5 cm. The ratio of velocities in two sections is

Question

An ideal fluid flows through a pipe of circular cross-section made of two sections with diameters 2.5 cm and 5 cm. The ratio of velocities in two sections is (A) 4: 1 (B) 1: 3 (C) 3: 1 (D) 9: 4

Tardigrade Admin · Accepted Answer

A1 V1=A2 v2 (v1/v2)=(A2/A1)=(r22/r12)=((5/2.5))2 (v1/v2)=4: 1

Q. An ideal fluid flows through a pipe of circular cross-section made of two sections with diameters $2.5 c m$ and $5 c m$ . The ratio of velocities in two sections is

$4 : 1$

$1 : 3$

$3 : 1$

$9 : 4$

$A_{1} V_{1} = A_{2} v_{2}$
$\frac{v _{1}}{v _{2}} = \frac{A _{2}}{A _{1}} = \frac{r _{2}^{2}}{r _{1}^{2}} = (\frac{5}{2.5})^{2}$
$\frac{v _{1}}{v _{2}} = 4 : 1$

Q. An ideal fluid flows through a pipe of circular cross-section made of two sections with diameters 2.5cm and 5cm. The ratio of velocities in two sections is

4:1

1:3

3:1

9:4