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Q. An ideal fluid flows through a pipe of circular cross-section made of two sections with diameters $2.5 \,cm$ and $5\, cm$. The ratio of velocities in two sections is

Solution:

$A_{1}\, V_{1}=A_{2}\, v_{2}$
$\frac{v_{1}}{v_{2}}=\frac{A_{2}}{A_{1}}=\frac{r_{2}^{2}}{r_{1}^{2}}=\left(\frac{5}{2.5}\right)^{2}$
$\frac{v_{1}}{v_{2}}=4: 1$