An equilibrium mixture in a vessel of capacity 100 litre contain 1 mol N2, 2 mol O2 and 3 mol NO . Find number of moles of O2 to be added, so that at new equilibrium the concentration of NO is 0.04 mol/lit. .

Question

An equilibrium mixture in a vessel of capacity 100 litre contain 1 mol N2, 2 mol O2 and 3 mol NO . Find number of moles of O2 to be added, so that at new equilibrium the concentration of NO is 0.04 mol/lit. . (A) (101/18) (B) (101/9) (C) (202/9) (D) None of these

Tardigrade Admin · Accepted Answer

N2+O2leftharpoons2NO K=(32/2 × 1) &hellip;(i) underset1 - zN2+ underset2 + y - zO2leftharpoons underset2 z + 32 N O K=((3+2 z)2/(2+y-z)(1-z)) (ii) Given, 3+2z=4 z=(1/2) (i) = (ii) y=(101/18)

Q. An equilibrium mixture in a vessel of capacity $100 l i t re$ contain $1 m o l$ $N_{2},$ $2 m o l$ $O_{2}$ and $3 m o l NO$ . Find number of moles of $O_{2}$ to be added, so that at new equilibrium the concentration of $NO$ is $0.04 m o l / l i t .$ .

$\frac{101}{18}$

$\frac{101}{9}$

$\frac{202}{9}$

None of these

$N_{2} + O_{2} ⇌ 2 NO$
$K = \frac{3 ^{2}}{2 \times 1}$ …(i)
$1 - z N_{2} + 2 + y - z O_{2} ⇌ 2 z + 3 2 NO$
$K = \frac{( 3 + 2 z ) ^{2}}{( 2 + y - z ) ( 1 - z )}$ (ii)
Given, $3 + 2 z = 4$
$z = \frac{1}{2}$
(i) = (ii)
$y = \frac{101}{18}$

Q. An equilibrium mixture in a vessel of capacity 100litre contain 1mol N2​, 2mol O2​ and 3molNO . Find number of moles of O2​ to be added, so that at new equilibrium the concentration of NO is 0.04mol/lit. .

18101​

9101​

9202​