An engine pump up 200 kg of water through a height of 20 m in 10 second. If the efficiency of the engine is 80 % Calculate the power of the engine.

Question

An engine pump up 200 kg of water through a height of 20 m in 10 second. If the efficiency of the engine is 80 % Calculate the power of the engine. (A) 3800 W (B) 5000 W (C) 4900 W (D) 4800 W

Tardigrade Admin · Accepted Answer

Output power =(mgh/t)=(200 × 9.8 × 20/10)=3920 watt ∴ η=(Po/Pi) ⇒ Pi=(Po/η)=(3920 × 100/80) =4900 watt

Q. An engine pump up $200 k g$ of water through a height of $20 m$ in $10$ second. If the efficiency of the engine is $80%$ Calculate the power of the engine.

$3800 W$

$5000 W$

$4900 W$

$4800 W$

Output power $= \frac{m g h}{t} = \frac{200 \times 9.8 \times 20}{10} = 3920$ watt
$∴ η = \frac{P _{o}}{P _{i}}$
$\Rightarrow P_{i} = \frac{P _{o}}{η} = \frac{3920 \times 100}{80}$
$= 4900$ watt

Q. An engine pump up 200kg of water through a height of 20m in 10 second. If the efficiency of the engine is 80% Calculate the power of the engine.

3800W

5000W

4900W

4800W