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  4. An engine pump up 200 kg of water through a height of 20 m in 10 second. If the efficiency of the engine is 80 % Calculate the power of the engine.

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Q. An engine pump up $200\, kg$ of water through a height of $20\, m$ in $10$ second. If the efficiency of the engine is $80 \%$ Calculate the power of the engine.

Work, Energy and Power

Solution:

Output power $=\frac{mgh}{t}=\frac{200 \times 9.8 \times 20}{10}=3920$ watt
$\therefore \eta=\frac{P_{o}}{P_{i}} $
$\Rightarrow P_{i}=\frac{P_{o}}{\eta}=\frac{3920 \times 100}{80}$
$=4900$ watt