An electron with values 4, 2, -2 and +1/2 for the set of four quantum numbers n, l, ml and s respectively, belongs to:

Question

An electron with values 4, 2, -2 and +1/2 for the set of four quantum numbers n, l, ml and s respectively, belongs to: (A)  4s orbital (B)  4p orbital (C)  4d orbital (D)  4f orbital

Tardigrade Admin · Accepted Answer

n=4 (4th Shell) l =2(d -sub shell) ml =-2(dx y orbital ) s =+(1/2)( uparrow) ldots (i) Hence, electron belongs to 4 d orbital.

Q. An electron with values $4, 2, - 2$ and $+ 1/2$ for the set of four quantum numbers $n, l, m_{l}$ and $s$ respectively, belongs to:

$4 s$ orbital

$4 p$ orbital

$4 d$ orbital

$4 f$ orbital

$n = 4$ (4th Shell)
$l = 2 (d$ -sub shell)
$m_{l} = - 2 (d_{x y}$ orbital )
$s = + \frac{1}{2} (↑) \dots$ (i)
Hence, electron belongs to $4 d$ orbital.

Q. An electron with values 4,2,−2 and +1/2 for the set of four quantum numbers n,l,ml​ and s respectively, belongs to:

4s orbital

4p orbital

4d orbital

4f orbital