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Q. An electron with values $4, 2, -2$ and $+1/2$ for the set of four quantum numbers $ n,\,\,l,\,\,{{m}_{l}} $ and $ s $ respectively, belongs to:

Punjab PMETPunjab PMET 2006Structure of Atom

Solution:

$n=4$ (4th Shell)
$l =2(d$ -sub shell)
$m_{l} =-2(d_{x y} $ orbital )
$s =+\frac{1}{2}(\uparrow) \ldots$ (i)
Hence, electron belongs to $4 d$ orbital.