An electron with speed v and a photon with speed c have the same de Broglie wavelength. If kinetic energy and momentum of electrons is Ee and pe and that of photon is Ep h and pp h respectively, then the correct statement is

Question

An electron with speed v and a photon with speed c have the same de Broglie wavelength. If kinetic energy and momentum of electrons is Ee and pe and that of photon is Ep h and pp h respectively, then the correct statement is (A) (Ee/Ep h)=(2 c/v) (B) (Ee/Ep h)=(v/2 c) (C) (pe/pp h)=(2 c/v) (D) (pe/pp h)=(v/2 c)

Tardigrade Admin · Accepted Answer

Correct answer is (b) (Ee/Ep h)=(v/2 c)

Q. An electron with speed $v$ and a photon with speed $c$ have the same de Broglie wavelength. If kinetic energy and momentum of electrons is $E_{e}$ and $p_{e}$ and that of photon is $E_{p h}$ and $p_{p h}$ respectively, then the correct statement is

$\frac{E _{e}}{E _{p h}} = \frac{2 c}{v}$

$\frac{E _{e}}{E _{p h}} = \frac{v}{2 c}$

$\frac{p _{e}}{p _{p h}} = \frac{2 c}{v}$

$\frac{p _{e}}{p _{p h}} = \frac{v}{2 c}$

Correct answer is (b) $\frac{E _{e}}{E _{p h}} = \frac{v}{2 c}$

Q. An electron with speed v and a photon with speed c have the same de Broglie wavelength. If kinetic energy and momentum of electrons is Ee​ and pe​ and that of photon is Eph​ and pph​ respectively, then the correct statement is

Eph​Ee​​=v2c​

Eph​Ee​​=2cv​

pph​pe​​=v2c​

pph​pe​​=2cv​