Question

An electron with speed $v$ and a photon with speed $c$ have the same de Broglie wavelength. If kinetic energy and momentum of electrons is $E_{e}$ and $p_{e}$ and that of photon is $E_{p h}$ and $p_{p h}$ respectively, then the correct statement is

• A. $\frac{E_{e}}{E_{p h}}=\frac{2 c}{v}$
• B. $\frac{E_{e}}{E_{p h}}=\frac{v}{2 c}$
• C. $\frac{p_{e}}{p_{p h}}=\frac{2 c}{v}$
• D. $\frac{p_{e}}{p_{p h}}=\frac{v}{2 c}$

Answer 1

Answer: (B)

Correct answer is (b) $\frac{E_{e}}{E_{p h}}=\frac{v}{2 c}$