An electron of mass m e and a proton of mass m p =1836 m e are moving with the same speed. The ratio of their de Broglie wavelength (λ text electron /λ text proton ) will be :

Question

An electron of mass m e and a proton of mass m p =1836 m e are moving with the same speed. The ratio of their de Broglie wavelength (λ text electron /λ text proton ) will be : (A) 1836 (B) 1 (C) 918 (D) (1/1836)

Tardigrade Admin · Accepted Answer

(λe/λp)=((h/me v)/(h)mp v)=1836

Q. An electron of mass $m_{e}$ and a proton of mass $m_{p} = 1836 m_{e}$ are moving with the same speed. The ratio of their de Broglie wavelength $\frac{λ _{electron}}{λ _{proton}}$ will be :

1836

1

918

$\frac{1}{1836}$

$\frac{λ _{e}}{λ _{p}} = \frac{\frac{h}{m _{e} v}}{\frac{h}{m _{p} v}} = 1836$

Q. An electron of mass me​ and a proton of mass mp​=1836me​ are moving with the same speed. The ratio of their de Broglie wavelength λproton ​λelectron ​​ will be :

1836

1

918

18361​

λp​λe​​=mp​vh​me​vh​​=1836

Q. An electron of mass $m_{e}$ and a proton of mass $m_{p} = 1836 m_{e}$ are moving with the same speed. The ratio of their de Broglie wavelength $\frac{λ _{electron}}{λ _{proton}}$ will be :

$\frac{1}{1836}$

$\frac{λ _{e}}{λ _{p}} = \frac{\frac{h}{m _{e} v}}{\frac{h}{m _{p} v}} = 1836$