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Q. An electron of mass $m _{ e }$ and a proton of mass $m _{ p }=1836 m _{ e }$ are moving with the same speed. The ratio of their de Broglie wavelength $\frac{\lambda_{\text {electron }}}{\lambda_{\text {proton }}}$ will be :

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Solution:

$\frac{\lambda_{e}}{\lambda_{p}}=\frac{\frac{h}{m_{e} v}}{\frac{h}{m_{p} v}}=1836$