An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. Its final velocity will be

Question

An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. Its final velocity will be (A) √ (2eV/m)  (B) √ (eV/m)  (C)  (eV/2m)  (D)  (eV/m) .

Tardigrade Admin · Accepted Answer

The kinetic energy of an electron (1/2)× mv2=eV or final velocity of electron (v) = √ (2eV/m).

Q. An electron of mass $m$ and charge e is accelerated from rest through a potential difference $V$ in vacuum. Its final velocity will be

$\frac{2 e V}{m}$

$\frac{e V}{m}$

$\frac{e V}{2 m}$

$\frac{e V}{m} .$

The kinetic energy of an electron
$\frac{1}{2} \times m v^{2} = e V$
or final velocity of electron $(v) = \frac{2 e V}{m} .$

Q. An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. Its final velocity will be

m2eV​​

meV​​

2meV​

meV​.