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Q. An electron of mass $m$ and charge e is accelerated from rest through a potential difference $V$ in vacuum. Its final velocity will be

AIPMTAIPMT 1996Dual Nature of Radiation and Matter

Solution:

The kinetic energy of an electron
$\frac {1}{2}\times mv^2=eV $
or final velocity of electron $(v) = \sqrt {\frac {2eV}{m}}. $