An electron jumps from 6th shell in an hydrogen atom, the number of Lyman emission lines will be

Question

An electron jumps from 6th shell in an hydrogen atom, the number of Lyman emission lines will be (A) 5 (B) 6 (C) 10 (D) 12

Tardigrade Admin · Accepted Answer

Total number of spectral lines obtained due to transition of electron from nth orbit to lower orbits is N=(n(n-1)/2) Here, n=6 ∴ N=(6(6-1)/2)=15 The number of Lyman lines will be five <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/2423466a2227409434b6078b17ecb49a-.jpeg" />

Q. An electron jumps from $6^{t h}$ shell in an hydrogen atom, the number of Lyman emission lines will be

$5$

$6$

$10$

$12$

Total number of spectral lines obtained due to transition of electron from $n^{t h}$ orbit to lower orbits is
$N = \frac{n ( n - 1 )}{2}$
Here, $n = 6$
$∴ N = \frac{6 ( 6 - 1 )}{2} = 15$
The number of Lyman lines will be five

Q. An electron jumps from 6th shell in an hydrogen atom, the number of Lyman emission lines will be

5

6

10

12

Total number of spectral lines obtained due to transition of electron from nth orbit to lower orbits is N=2n(n−1)​ Here, n=6 ∴N=26(6−1)​=15 The number of Lyman lines will be five

Q. An electron jumps from $6^{t h}$ shell in an hydrogen atom, the number of Lyman emission lines will be

$5$

$6$

$10$

$12$

Total number of spectral lines obtained due to transition of electron from $n^{t h}$ orbit to lower orbits is
$N = \frac{n ( n - 1 )}{2}$
Here, $n = 6$
$∴ N = \frac{6 ( 6 - 1 )}{2} = 15$
The number of Lyman lines will be five