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Q.
An electron jumps from $6^{th}$ shell in an hydrogen atom, the number of Lyman emission lines will be
UP CPMTUP CPMT 2009
Solution:
Total number of spectral lines obtained due to transition of electron from $n^{th}$ orbit to lower orbits is
$N=\frac{n(n-1)}{2}$
Here, $n=6$
$\therefore N=\frac{6(6-1)}{2}=15$
The number of Lyman lines will be five
