An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227 × 10-2nm, the potential difference is :

Question

An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227 × 10-2nm, the potential difference is : (A) 10 V (B) 102 V (C) 103 V (D) 104 V

Tardigrade Admin · Accepted Answer

λ = 1.227 × 10-2 m =0.1227 mathringA λ=(12.27/√V) mathringA 0.1227 = (12.27/√V) mathringA √V×102 ⇒ V=104

Q. An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is $1.227 \times 1 0^{- 2} nm$ , the potential difference is :

$10$ V

$1 0^{2}$ V

$1 0^{3}$ V

$1 0^{4}$ V

$λ = 1.227 \times 1 0^{- 2} m$
$= 0.1227 \overset{˚}{A}$
$λ = \frac{12.27}{V} \overset{˚}{A}$
$0.1227 = \frac{12.27}{V} \overset{˚}{A}$
$V \times 1 0^{2}$
$\Rightarrow V = 1 0^{4}$

Q. An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227×10−2nm, the potential difference is :

10 V

102 V

103 V

104 V