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  4. An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227 × 10-2nm, the potential difference is :

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Q. An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is $1.227 \times 10^{-2}nm$, the potential difference is :

NEETNEET 2020Dual Nature of Radiation and Matter

Solution:

$\lambda = 1.227 \times 10^{-2}\,m$
$=0.1227 \, \mathring{A}$
$\lambda=\frac{12.27}{\sqrt{V}} \mathring{A}$
$0.1227 = \frac{12.27}{\sqrt{V}} \mathring{A}$
$\sqrt{V}\times10^{2} $
$\Rightarrow V=10^{4}$