An electron in hydrogen atom after absorbing an energy photon jumps from energy state n1 to n2 Then it returns to ground state after emitting six different wavelengths in emission spectrum. The energy of emitted photons is either equal to, less than or greater than the absorbed photons. Then n1 and n2 are

Question

An electron in hydrogen atom after absorbing an energy photon jumps from energy state n1 to n2 Then it returns to ground state after emitting six different wavelengths in emission spectrum. The energy of emitted photons is either equal to, less than or greater than the absorbed photons. Then n1 and n2 are (A) n2 = 4,n1=3 (B) n2 = 5,n2=3 (C) n2 = 4,n1=2 (D) n2 = 4,n1=1

Tardigrade Admin · Accepted Answer

From n2 = 4, six lines are obtained in emission spectrum. Now: E4 - 2 = Eadsorbed E4 arrow 3 < Eadsorbed and E4 - 1 E3 - 1, E2 - 1 > Eadsorbed Hence, n1 = 2 and n2 = 4

$n_{2} = 4, n_{1} = 3$

$n_{2} = 5, n_{2} = 3$

$n_{2} = 4, n_{1} = 2$

$n_{2} = 4, n_{1} = 1$

From $n_{2}$ = 4, six lines are obtained in emission spectrum.
Now : $E_{4 - 2} = E_{a d sor b e d}$
$E_{4 \to 3} < E_{a d sor b e d}$
and $E_{4 - 1} E_{3 - 1}, E_{2 - 1} > E_{a d sor b e d}$
Hence, $n_{1}$ = 2 and $n_{2}$ = 4

n2​=4,n1​=3

n2​=5,n2​=3

n2​=4,n1​=2

n2​=4,n1​=1

From n2​ = 4, six lines are obtained in emission spectrum. Now : E4−2​=Eadsorbed​ E4→3​<Eadsorbed​ and E4−1​E3−1​,E2−1​>Eadsorbed​ Hence, n1​ = 2 and n2​ = 4

$n_{2} = 4, n_{1} = 3$

$n_{2} = 5, n_{2} = 3$

$n_{2} = 4, n_{1} = 2$

$n_{2} = 4, n_{1} = 1$

From $n_{2}$ = 4, six lines are obtained in emission spectrum.
Now : $E_{4 - 2} = E_{a d sor b e d}$
$E_{4 \to 3} < E_{a d sor b e d}$
and $E_{4 - 1} E_{3 - 1}, E_{2 - 1} > E_{a d sor b e d}$
Hence, $n_{1}$ = 2 and $n_{2}$ = 4