An electron and a positron each of mass (1/2000) amu annihilate each other and produce two photons of equal energy The minimum energy of each photon produced, will be :

Question

An electron and a positron each of mass (1/2000) amu annihilate each other and produce two photons of equal energy The minimum energy of each photon produced, will be : (A) 0.0465 MeV (B) 4.65 MeV (C) 0.465 MeV (D) 0.565 MeV

Tardigrade Admin · Accepted Answer

Mass equivalent to each photon =(1/2000)amu Energy of each photon is =(1/2000)× 931MeV =0.465MeV

Q. An electron and a positron each of mass $\frac{1}{2000}$ amu annihilate each other and produce two photons of equal energy The minimum energy of each photon produced, will be :

0.0465 MeV

4.65 MeV

0.465 MeV

0.565 MeV

Mass equivalent to each photon $= \frac{1}{2000} am u$ Energy of each photon is $= \frac{1}{2000} \times 931 M e V$ $= 0.465 M e V$

Q. An electron and a positron each of mass 20001​ amu annihilate each other and produce two photons of equal energy The minimum energy of each photon produced, will be :