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  4. An electron and a positron each of mass (1/2000) amu annihilate each other and produce two photons of equal energy The minimum energy of each photon produced, will be :

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Q. An electron and a positron each of mass $ \frac{1}{2000} $ amu annihilate each other and produce two photons of equal energy The minimum energy of each photon produced, will be :

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Solution:

Mass equivalent to each photon $ =\frac{1}{2000}amu $ Energy of each photon is $ =\frac{1}{2000}\times 931MeV $ $ =0.465MeV $