An electromagnetic wave is propagating in vacuum along z-axis, the electric field component is given by Ex=E0 sin (k z-ω t), then magnetic component is

Question

An electromagnetic wave is propagating in vacuum along z-axis, the electric field component is given by Ex=E0 sin (k z-ω t), then magnetic component is (A) Bx=(E0/C) sin (k z-ω t) (B) By=(B0/C) sin (k z-ω t) (C) By=(E0/C) sin (k z-ω t) (D) By=B0 C sin (k z-ω t)

Tardigrade Admin · Accepted Answer

Direction of propagation arrow Z Ex=E0 sin (k Z-ω t) vecB arrow will be in the y -direction ∴ By=B0 sin (k Z-ω t) ∴ (E0/B0)=c B0=(E0/c) So, By=(E0/c) sin (k Z-ω t)

Q. An electromagnetic wave is propagating in vacuum along $z$ -axis, the electric field component is given by $E_{x} = E_{0}$ $sin (k z - ω t)$ , then magnetic component is

$B_{x} = \frac{E _{0}}{C} sin (k z - ω t)$

$B_{y} = \frac{B _{0}}{C} sin (k z - ω t)$

$B_{y} = \frac{E _{0}}{C} sin (k z - ω t)$

$B_{y} = B_{0} C sin (k z - ω t)$

Direction of propagation $\to Z$
$E_{x} = E_{0} sin (k Z - ω t)$
$B \to$ will be in the $y$ -direction
$∴ B_{y} = B_{0} sin (k Z - ω t)$
$∴ \frac{E _{0}}{B _{0}} = c$
$B_{0} = \frac{E _{0}}{c}$
So, $B_{y} = \frac{E _{0}}{c} sin (k Z - ω t)$

Q. An electromagnetic wave is propagating in vacuum along z-axis, the electric field component is given by Ex​=E0​ sin(kz−ωt), then magnetic component is

Bx​=CE0​​sin(kz−ωt)

By​=CB0​​sin(kz−ωt)

By​=CE0​​sin(kz−ωt)

By​=B0​Csin(kz−ωt)