Question

An electromagnetic wave is propagating in vacuum along $z$-axis, the electric field component is given by $E_{x}=E_{0}$ $\sin (k z-\omega t)$, then magnetic component is

• A. $B_{x}=\frac{E_{0}}{C} \sin (k z-\omega t)$
• B. $B_{y}=\frac{B_{0}}{C} \sin (k z-\omega t)$
• C. $B_{y}=\frac{E_{0}}{C} \sin (k z-\omega t)$
• D. $B_{y}=B_{0} C \sin (k z-\omega t)$

Answer 1

Answer: (C)

Direction of propagation $\rightarrow Z$
$E_{x}=E_{0} \sin (k Z-\omega t) $
$\vec{B} \rightarrow $ will be in the $ y $ -direction
$\therefore B_{y}=B_{0} \sin (k Z-\omega t)$
$\therefore \frac{E_{0}}{B_{0}}=c$
$B_{0}=\frac{E_{0}}{c}$
So, $B_{y}=\frac{E_{0}}{c} \sin (k Z-\omega t)$