Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
An electric field is given by Ex=-2 x3 hati N / C. The potential of the point (1,-2), if potential of the point (2,4) is taken as zero, is
Q. An electric field is given by
E
x
=
−
2
x
3
i
^
N
/
C
. The potential of the point
(
1
,
−
2
)
, if potential of the point
(
2
,
4
)
is taken as zero, is
2971
253
Electrostatic Potential and Capacitance
Report Error
A
−
7.5
×
1
0
3
V
37%
B
7.5
×
1
0
3
V
30%
C
−
15
×
1
0
3
V
20%
D
15
×
1
0
3
V
13%
Solution:
d
V
=
−
E
⋅
d
r
=
−
(
−
2
x
3
i
^
)
⋅
(
d
x
i
^
+
d
y
j
^
+
d
z
k
^
)
=
2
x
3
d
x
⇒
0
∫
V
d
V
=
2
∫
1
(
2
x
3
)
×
1
0
3
d
x
V
=
−
7.5
×
1
0
3
V