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Q. An electric field is given by $E_{x}=-2 x^{3} \hat{i} N / C$. The potential of the point $(1,-2)$, if potential of the point $(2,4)$ is taken as zero, is

Electrostatic Potential and Capacitance

Solution:

$d V=-\vec{E} \cdot d \vec{r}=-\left(-2 x^{3} \hat{i}\right) \cdot(d x \hat{i}+d y \hat{j}+d z \hat{k})$
$=2 x^{3} d x$
$\Rightarrow \int\limits_{0}^{V} d V=\int\limits_{2}^{1}\left(2 x^{3}\right) \times 10^{3} d x$
$V= -7.5 \times 10^{3} V$