An electric discharge is passed through a mixture containing 50 c.c. of O2 and 50 c.c. of H2. The volume of the gases formed (i) at room temperature and (ii) at 110° C will be

Question

An electric discharge is passed through a mixture containing 50 c.c. of O2 and 50 c.c. of H2. The volume of the gases formed (i) at room temperature and (ii) at 110° C will be (A) (i) 25 c.c. (ii) 50 c.c. (B) (i) 50 c.c. (ii) 75 c.c. (C) (i) 25 c.c. (ii) 15 c.c. (D) (i) 15 c.c. (ii) 15 c.c

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/efa6e16a9c6fa2489e0549fd54f54cc6-.png" /> In this case H2 is limiting reagent x = 25ml undersett = t textAt 110° C underset02H(g) + underset25mlO(2(g) → underset50ml2H2O(g) Vgas = 75 ml

Q. An electric discharge is passed through a mixture containing $50 c . c .$ of $O_{2}$ and $50 c . c .$ of $H_{2}$ . The volume of the gases formed (i) at room temperature and (ii) at $11 0^{\circ} C$ will be

$(i) 25 c . c . (ii) 50 c . c .$

$(i) 50 c . c . (ii) 75 c . c .$

$(i) 25 c . c . (ii) 15 c . c .$

$(i) 15 c . c . (ii) 15 c . c$

In this case $H_{2}$ is limiting reagent $x = 25$ ml
$t = t At 11 0^{\circ} C 0 2 H_{(g)} + 25 m l O_{(2 (g)} \to 50 m l 2 H_{2} O_{(g)}$
$V_{g a s} = 75 m l$

Q. An electric discharge is passed through a mixture containing 50c.c. of O2​ and 50c.c. of H2​. The volume of the gases formed (i) at room temperature and (ii) at 110∘C will be

(i)25c.c.(ii)50c.c.

(i)50c.c.(ii)75c.c.

(i)25c.c.(ii)15c.c.

(i)15c.c.(ii)15c.c