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Q. An electric discharge is passed through a mixture containing $50\, c.c.$ of $O_2$ and $50\, c.c.$ of $H_2$. The volume of the gases formed (i) at room temperature and (ii) at $110^{\circ} C$ will be

Some Basic Concepts of Chemistry

Solution:

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In this case $H_2$ is limiting reagent $x = 25$ml
$\underset{t = t}{\text{At} 110^{\circ} C} \,\underset{0}{2H_{(g)}} + \underset{25ml}{O_{(2(g)}} \to \underset{50ml}{2H_2O_{(g)}} $
$V_{gas} = 75\,ml$