An electric dipole of length 2 cm is placed with its axis making an angle of 30° to a uniform electric field 105 N / C. If it experiences a torque of 10 √3 Nm, then potential energy of the dipole

Question

An electric dipole of length 2 cm is placed with its axis making an angle of 30° to a uniform electric field 105 N / C. If it experiences a torque of 10 √3 Nm, then potential energy of the dipole (A) - 10 J (B) - 20 J (C) - 30 J (D) - 40 J

Tardigrade Admin · Accepted Answer

10 √3=P 105 (1/2) 2 √3 × 10-4=P U=-2 √3 × 10-4 × 105 × (√3/2) U=-3 × 10 U=-30 J

Q. An electric dipole of length $2 c m$ is placed with its axis making an angle of $3 0^{\circ}$ to a uniform electric field $1 0^{5} N / C$ . If it experiences a torque of $103 N m$ , then potential energy of the dipole

- 10 J

- 20 J

- 30 J

- 40 J

$103 = P 1 0^{5} \frac{1}{2}$
$23 \times 1 0^{- 4} = P$
$U = - 23 \times 1 0^{- 4} \times 1 0^{5} \times \frac{3}{2}$
$U = - 3 \times 10$
$U = - 30 J$

Q. An electric dipole of length 2cm is placed with its axis making an angle of 30∘ to a uniform electric field 105N/C. If it experiences a torque of 103​Nm, then potential energy of the dipole