An electric dipole is placed at an angle 60° with an electric field of strength 4 × 105 N / C. It experiences a torque equal to 8 √3 . Calculate the charge on the dipole, if dipole is of length 4 cm

Question

An electric dipole is placed at an angle 60° with an electric field of strength 4 × 105 N / C. It experiences a torque equal to 8 √3 . Calculate the charge on the dipole, if dipole is of length 4 cm (A) 10-1 C (B) 10-2 C (C) 10-3 C (D) 10-4 C

Tardigrade Admin · Accepted Answer

τ=P E sin θ 8 √3=[q × 4 × 102] .4 × 105 sin 60° find q=10-3

Q. An electric dipole is placed at an angle $6 0^{\circ}$ with an electric field of strength $4 \times 1 0^{5} N / C$ . It experiences a torque equal to $83$ . Calculate the charge on the dipole, if dipole is of length $4 c m$

$1 0^{- 1} C$

$1 0^{- 2} C$

$1 0^{- 3} C$

$1 0^{- 4} C$

$τ = PE sin θ$
$83 = [q \times 4 \times 1 0^{2}] .4 \times 1 0^{5} sin 6 0^{\circ}$
find $q = 1 0^{- 3}$

Q. An electric dipole is placed at an angle 60∘ with an electric field of strength 4×105N/C. It experiences a torque equal to 83​. Calculate the charge on the dipole, if dipole is of length 4cm

10−1C

10−2C

10−3C

10−4C