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Q. An electric dipole is placed at an angle $60^{\circ}$ with an electric field of strength $4 \times 10^{5} N / C$. It experiences a torque equal to $8 \sqrt{3} \,$. Calculate the charge on the dipole, if dipole is of length $4 \,cm$

Electric Charges and Fields

Solution:

$\tau=P E \sin \theta$
$8 \sqrt{3}=\left[q \times 4 \times 10^{2}\right] .4 \times 10^{5} \sin 60^{\circ}$
find $q=10^{-3}$