An electric current 0.25 ampere was passed hrough acidified water for two hours,the volume of H2 produced at N.T.P. is

Question

An electric current 0.25 ampere was passed hrough acidified water for two hours,the volume of H2 produced at N.T.P. is (A) 20.16 litres (B) 0.2016 litres (C) 2.016 litres (D) 0.4032 litres

Tardigrade Admin · Accepted Answer

W = (E/96500)× I × t = (1/96500)× 0.25 ×2 × 60 = 0.01865 g 2g H2 has volume = 22.4 litre 0.01865 g of H2 has volume = (22.4/2)× 0.01865 = 0.2016 litre

Q. An electric current 0.25 ampere was passed hrough acidified water for two hours,the volume of $H_{2}$ produced at N.T.P. is

20.16 litres

0.2016 litres

2.016 litres

0.4032 litres

$W = \frac{E}{96500} \times I \times t$
$= \frac{1}{96500} \times 0.25 \times 2 \times 60$
$= 0.01865 g$
$2 g H_{2}$ has volume $= 22.4$ litre
$0.01865 g$ of $H_{2}$ has volume
$= \frac{22.4}{2} \times 0.01865$
$= 0.2016$ litre

Q. An electric current 0.25 ampere was passed hrough acidified water for two hours,the volume of H2​ produced at N.T.P. is