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Q. An electric current 0.25 ampere was passed hrough acidified water for two hours,the volume of $H_2$ produced at N.T.P. is

Electrochemistry

Solution:

$W = \frac{E}{96500}\times I \times t$
$ = \frac{1}{96500}\times 0.25 \times2 \times 60$
$= 0.01865 \,g $
$2g H_{2}$ has volume $= 22.4$ litre
$ 0.01865\, g$ of $H_{2}$ has volume
$= \frac{22.4}{2}\times 0.01865$
$= 0.2016$ litre