An astronomical telescope has focal lengths 100 and 10cm of objective and eyepiece lens respectively when the final image is formed at least distance of distinct vision, the magnification power of telescope will be

Question

An astronomical telescope has focal lengths 100 and 10cm of objective and eyepiece lens respectively when the final image is formed at least distance of distinct vision, the magnification power of telescope will be (A) -10 (B) -11 (C) -14 (D) -15

Tardigrade Admin · Accepted Answer

MP=(- f0/fe)(1 + (fe/D)) MP=(- 100/10)(1 + (10/25)) MP=-14

Q. An astronomical telescope has focal lengths $100$ and $10 c m$ of objective and eyepiece lens respectively when the final image is formed at least distance of distinct vision, the magnification power of telescope will be

$- 10$

$- 11$

$- 14$

$- 15$

$MP = \frac{- f _{0}}{f _{e}} (1 + \frac{f _{e}}{D})$
$MP = \frac{- 100}{10} (1 + \frac{10}{25})$
$MP = - 14$

Q. An astronomical telescope has focal lengths 100 and 10cm of objective and eyepiece lens respectively when the final image is formed at least distance of distinct vision, the magnification power of telescope will be

−10

−11

−14

−15