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Q. An astronomical telescope has focal lengths $100$ and $10cm$ of objective and eyepiece lens respectively when the final image is formed at least distance of distinct vision, the magnification power of telescope will be

NTA AbhyasNTA Abhyas 2020

Solution:

$MP=\frac{- f_{0}}{f_{e}}\left(1 + \frac{f_{e}}{D}\right)$
$MP=\frac{- 100}{10}\left(1 + \frac{10}{25}\right)$
$MP=-14$