An aqueous solution of HCl is 10-9 M HCl. The pOH of the solution should be

Question

An aqueous solution of HCl is 10-9 M HCl. The pOH of the solution should be (A) 9 (B) between 7 and 8 (C) 5 (D) unpredictable

Tardigrade Admin · Accepted Answer

pH of 10-9 M HCl is in between 6 and 7 (since it is very dilute and H + from water cannot be neglected.) ∴ Total [ H +]=10-9+10-7=1.01 × 10-7 Hence, pOH will be the between 7 and 8 .

Q. An aqueous solution of $H Cl$ is $1 0^{- 9} M H Cl$ . The $pO H$ of the solution should be

9

between 7 and 8

5

unpredictable

$p H$ of $1 0^{- 9} M H Cl$ is in between $6$ and $7$ (since it is very dilute and $H^{+}$ from water cannot be neglected.)
$∴$ Total $[H^{+}] = 1 0^{- 9} + 1 0^{- 7} = 1.01 \times 1 0^{- 7}$
Hence, $pO H$ will be the between $7$ and $8$ .

Q. An aqueous solution of HCl is 10−9MHCl. The pOH of the solution should be

9

between 7 and 8

5

unpredictable

pH of 10−9MHCl is in between 6 and 7 (since it is very dilute and H+ from water cannot be neglected.) ∴ Total [H+]=10−9+10−7=1.01×10−7 Hence, pOH will be the between 7 and 8 .

Q. An aqueous solution of $H Cl$ is $1 0^{- 9} M H Cl$ . The $pO H$ of the solution should be

$p H$ of $1 0^{- 9} M H Cl$ is in between $6$ and $7$ (since it is very dilute and $H^{+}$ from water cannot be neglected.)
$∴$ Total $[H^{+}] = 1 0^{- 9} + 1 0^{- 7} = 1.01 \times 1 0^{- 7}$
Hence, $pO H$ will be the between $7$ and $8$ .