Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
An aqueous solution of 98 %( w / w ) H 2 SO 4 has density of 1.02 g / cc. The Molality of the solution is
Q. An aqueous solution of
98%
(
w
/
w
)
H
2
S
O
4
has density of
1.02
g
/
cc
. The Molality of the solution is
2575
189
TS EAMCET 2020
Report Error
A
1.1
B
0,7
C
2.1
D
1.5
Solution:
∵
Volume
=
Density
(
d
)
Mass
(
m
)
=
1.02
100
=
98.039
m
L
∴
Molarity
=
98
×
98.04
9.8
×
1000
=
1.01
Which is close to
1.1
.